Let's say that Io orbits the Earth at the same distance as it orbits Jupiter - 421,700 km. Using Kepler's third law to compare the moon and Io :
D^3 = T^2
(384,000/421,700)^3 = T^2
T = 0.868
So, if the moon takes 27.3 days to orbit Earth, then Io will take 1.132 (1-0.868) times longer, viz, 31 days.
We can then use the distance squared law to calculate the new velocity for Io.
D^2 = T/V
0.91^2 = 0.868 / V
0.828 = 0.868 / V
V = 0.868 / 0.828 = 1.048
This means that the moon's velocity will be 1.048 times that of Io. Given that the moon's velocity is circa 3,683 km/hr , this means Io's new Earth bound velocity would be 3,514 km/hr or 0.976 km/s.
The square root of the ratio of the masses of two central bodies is equal to the orbital factor of their orbital bodies.
Jupiter has a mass of 317.83 times that of Earth :
The square root of 317.83 is 17.82 (a small rounding difference with 17.72 in the above table).
In Part One I showed that the square root of the ratio of the masses also works for Jupiter and The Sun :
The square root of 1047.36 is 32.36.
Therefore, we would expect that the Sun would have an orbital factor of 576.6 times that of Earth (17.82 x 32.36).
NASA states that the Sun has a mass of 333,000 times that of Earth.
The square root of 333,000 is 577.
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